Ljubač, Zadar County
Ljubač | |
|---|---|
  Ljubač | |
| Coordinates: 44°15′38″N 15°17′44″E / 44.2604552100°N 15.2954272700°E | |
| Country |  Croatia |
| County | Zadar |
| Municipality | Ražanac |
| Area | |
• Total | 7.6 km2 (2.9 sq mi) |
| Population (2021)[2] | |
• Total | 402 |
| • Density | 53/km2 (140/sq mi) |
| Time zone | UTC+1 (CET) |
| • Summer (DST) | UTC+2 (CEST) |
Ljubač is a small Croatian village located north of Zadar. It is part of the municipality of Ražanac and the population is 475[3] as of the 2011 census. Ljubač is located 15 kilometres north of Zadar, with a view of Velebit and Pag.
References
- ^ Register of spatial units of the State Geodetic Administration of the Republic of Croatia. Wikidata Q119585703.
- ^ "Population by Age and Sex, by Settlements" (xlsx). Census of Population, Households and Dwellings in 2021. Zagreb: Croatian Bureau of Statistics. 2022.
- ^ "Population by Age and Sex, by Settlements, 2011 Census: Ljubač". Census of Population, Households and Dwellings 2011. Zagreb: Croatian Bureau of Statistics. December 2012.
Wikimedia Commons has media related to Ljubač, Zadar County.