1955 World Table Tennis Championships – Women's singles

1955 Women's singles
Main article: 1955 World Table Tennis Championships

The 1955 World Table Tennis Championships women's singles was the 22nd edition of the women's singles championship.[1][2] Angelica Rozeanu defeated Ermelinde Rumpler-Wertl in the final by three sets to nil, to win a sixth consecutive title.[3]

Results

Round of 16 Quarterfinals Semifinals Final
Romania Angelica Rozeanu 3
France Christiane Watel 0 Romania Rozeanu 21 16 21 21
England Rosalind Rowe 21 21 21 England Rowe R 15 21 19 12
Czechoslovakia Libuše Grafková 9 17 14 Romania Rozeanu 21 21 21
Japan Kiiko Watanabe 21 21 21 Japan Watanabe 10 11 17
England Jill Rook 9 17 6 Japan Watanabe 21 21 18 21
Romania Sári Szász-Kolozsvári 3 Romania Szasz 11 16 21 9
Wales Audrey Bates 0 Romania Rozeanu 21 21 21
Romania Ella Zeller 1 Austria Rumpler-Wertl 13 5 8
Austria Ermelinde Rumpler-Wertl 3 Austria Rumpler-Wertl 21 13 21 21
England Ann Haydon 21 16 21 24 England Haydon 19 21 10 16
Japan Yoshiko Tanaka 18 21 19 22 Austria Rumpler-Wertl 21 18 13 21 21
Hungary Éva Kóczián 3 Hungary Kóczián 15 21 21 11 17
Sweden Birgitta Tegner 1 Hungary Kóczián 25 17 21 21
England Diane Rowe 16 21 21 22 England Rowe D 23 21 17 13
Japan Fujie Eguchi 21 13 15 20

See also

List of World Table Tennis Championships medalists

References

  1. ^ "List of Winners". All About Tennis.
  2. ^ "1955 results" (PDF). International Table Tennis Federation. Archived from the original (PDF) on 2012-04-12.
  3. ^ Montague, Trevor (2004). A-Z of Sport, pages 699-700. The Bath Press. ISBN 0-316-72645-1.


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