1840 United States presidential election in New York|
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| Turnout | 91.9%[1]  21.4 pp |
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 County Results
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Harrison
40–50% 50–60% 60–70%
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Van Buren
40–50% 50–60% 60–70% 70–80%
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A presidential election was held in New York from November 2–4, 1840 as part of the 1840 United States presidential election.[2] Voters chose 42 representatives, or electors to the Electoral College, who voted for President and Vice President.
New York voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won New York by a narrow margin of 3.00%.
Results
See also
References
- ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
- ^ "1840 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved December 23, 2013.
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- See also
- Presidential elections
- Senate elections
- House elections
- Gubernatorial elections
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