1806 United States House of Representatives election in Delaware

1806 United States House of Representatives election in Delaware
October 7, 1806 (1806-10-07)
 
Candidate James M. Broom Thomas Fitzgerald
Party Federalist Democratic-Republican
Popular vote 2,353 830
Percentage 60.52% 21.35%
 
Candidate Joseph Haslet Thomas Montgomery
Party Democratic-Republican Democratic-Republican
Popular vote 382 323
Percentage 9.83% 8.31%
U.S. representative before election

James M. Broom
Federalist

Elected U.S. representative

James M. Broom
Federalist

The 1806 United States House of Representatives election in Delaware was held on October 7, 1806, to elect the U.S. representative from Delaware's at-large congressional district. Incumbent Federalist James M. Broom faced re-election to a full term after winning the previous year's special election. He was challenged by three Democratic-Republicans.

Broom was re-elected with over 60% of the vote, with neither opponent coming close to unseating him.

Results

1806 United States House of Representatives election in Delaware[1]
Party Candidate Votes %
Federalist James M. Broom (incumbent) 2,353 60.52
Democratic-Republican Thomas Fitzgerald 830 21.35
Democratic-Republican Joseph Haslet 382 9.83
Democratic-Republican Thomas Montgomery 323 8.31
Majority 1,523 39.17
Total votes 3,888 100.00
Federalist hold

Results by county

County Broom# Broom% Fitzgerald# Fitzgerald% Haslet# Haslet% Montgomery# Montgomery% Total
Kent 709 95.94% 30 4.06% 739
New Castle 928 43.36% 830 38.79% 382 17.85% 2,140
Sussex 719 71.05% 293 28.95% 1,012

See also

References

  1. ^ "Our Campaigns - DE District At Large Race - Oct 07, 1806". Our Campaigns. January 10, 2006.


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